Short Answer

Determine which of the matrices in Exercises 1–6 are symmetric.
\(\left( {\begin{array}{{}{}}1&2&2&1\\2&2&2&1\\2&2&1&2\end{array}} \right)\)

The given matrix is not symmetric.

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Find the transpose

A matrix\(A\) with, \(n \times n\) dimension, is symmetric if it satisfies the equation\({A^T} = A\).

It is given that\(A = \left( {\begin{array}{{}{}}1&2&2&1\\2&2&2&1\\2&2&1&2\end{array}} \right)\). It can be noted that \(A\) is not a square matrix of \(n \times n\) dimension.

Step 2: Draw the conclusion

As \(A\) is not square matrix, so it cannot be asymmetric matrix.

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Linear Algebra and its Applications

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Short Answer

Determine which of the matrices in Exercises 1–6 are symmetric.
\(\left( {\begin{array}{{}{}}1&2&2&1\\2&2&2&1\\2&2&1&2\end{array}} \right)\)

Step by Step Solution

Step 1: Find the transpose

Step 2: Draw the conclusion

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Linear Algebra and its Applications

Answers without the blur.

Short Answer

Determine which of the matrices in Exercises 1–6 are symmetric.\(\left( {\begin{array}{{}{}}1&2&2&1\\2&2&2&1\\2&2&1&2\end{array}} \right)\)

Step by Step Solution

Step 1: Find the transpose

Step 2: Draw the conclusion

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Determine which of the matrices in Exercises 1–6 are symmetric.
\(\left( {\begin{array}{{}{}}1&2&2&1\\2&2&2&1\\2&2&1&2\end{array}} \right)\)