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Q11E

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Linear Algebra and its Applications
Found in: Page 437
Linear Algebra and its Applications

Linear Algebra and its Applications

Book edition 5th
Author(s) David C. Lay, Steven R. Lay and Judi J. McDonald
Pages 483 pages
ISBN 978-03219822384

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Short Answer

Explain why any set of five or more points in \({\mathbb{R}^3}\) must be affinely dependent.

Any set of five or more points in \({\mathbb{R}^3}\) must be affinely dependent.

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Step by Step Solution

Step 1: State the condition for affinely dependence

The set is said to be affinely dependent if the set \(\left\{ {{{\bf{v}}_{\bf{1}}},{{\bf{v}}_{\bf{2}}},...,{{\bf{v}}_p}} \right\}\) in the dimension\({\mathbb{R}^n}\) exists such that for non-zero scalars\({c_1},{c_2},...,{c_p}\), the sum of scalars is zero i.e.\({c_1} + {c_2} + ... + {c_p} = 0\), and \({c_1}{{\bf{v}}_1} + {c_2}{{\bf{v}}_2} + ... + {c_p}{{\bf{v}}_p} = 0\).

Step 2: Show affinely dependence

Consider the set of five points \(\left\{ {{{\bf{v}}_1},{{\bf{v}}_2},{{\bf{v}}_3},{{\bf{v}}_4},{{\bf{v}}_5}} \right\}\).

Let \(\left\{ {{{\bf{v}}_2} - {{\bf{v}}_1},{{\bf{v}}_3} - {{\bf{v}}_1},{{\bf{v}}_4} - {{\bf{v}}_1},{{\bf{v}}_5} - {{\bf{v}}_1}} \right\}\) be the set of vectors in \({\mathbb{R}^3}\).This new set of four points must be linearly dependent when a set of vectors is translated by eliminating the first point or any other point.

From \({\mathbb{R}^3}\), the number of entries is 3. From the above-considered set of points, the number of vectors is 4. That is, \(n = 3\), and \(p = 4\).

Here, the set contains more vectors or points than the number of entries. So,\(p > n\)and the original set of five points \(\left\{ {{{\bf{v}}_1},{{\bf{v}}_2},{{\bf{v}}_3},{{\bf{v}}_4},{{\bf{v}}_5}} \right\}\) is affinely dependent.

Therefore, any set of five or more points in \({\mathbb{R}^3}\) must be affinely dependent.

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