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Q27E
Expert-verifiedQuestion: 27. Give an example of a closed subset \(S\) of \({\mathbb{R}^{\bf{2}}}\) such that \({\rm{conv}}\,S\) is not closed.
The set is \(S = \left\{ {\left( {x,y} \right):{x^2}{y^2} = 1,\,\,y > 0} \right\}\).
One of the possible sets is \(S = \left\{ {\left( {x,y} \right):{x^2}{y^2} = 1,\,\,y > 0} \right\}\). This set is not closed as the equation \({x^2}{y^2} = 1,\,\,\,y > 0\) is of a hyperbola in an upper half-plane that is shown below:
The hyperbola \(xy = 1\) opens upwards; that is, it satisfies all values of \(x\) and for \(y > 0\).
So, the set \(S\) is in \({\mathbb{R}^{\bf{2}}}\).
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