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Q7E

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Linear Algebra and its Applications
Found in: Page 437
Linear Algebra and its Applications

Linear Algebra and its Applications

Book edition 5th
Author(s) David C. Lay, Steven R. Lay and Judi J. McDonald
Pages 483 pages
ISBN 978-03219822384

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Short Answer

Question: In Exercise 7, let H be the hyperplane through the listed points. (a) Find a vector n that is normal to the hyperplane. (b) Find a linear functional f and a real number d such that \(H = \left( {f:d} \right)\).

7. \(\left( {\begin{array}{*{20}{c}}{\bf{1}}\\{\bf{1}}\\{\bf{3}}\end{array}} \right),\left( {\begin{array}{*{20}{c}}{\bf{2}}\\{\bf{4}}\\{\bf{1}}\end{array}} \right),\left( {\begin{array}{*{20}{c}}{ - {\bf{1}}}\\{ - {\bf{2}}}\\{\bf{5}}\end{array}} \right)\)

  1. The normal vector is \(n = \left( {\begin{array}{*{20}{c}}0\\2\\3\end{array}} \right)\) or a multiple
  2. The linear function is \(f\left( x \right) = 2{x_2} + 3{x_3}\) , and the real number is \(d = 11\).
See the step by step solution

Step by Step Solution

Step 1: Write the given data

Let \({v_1} = \left( {\begin{array}{*{20}{c}}1\\1\\3\end{array}} \right)\), \({v_2} = \left( {\begin{array}{*{20}{c}}2\\4\\1\end{array}} \right)\), and \({v_3} = \left( {\begin{array}{*{20}{c}}{ - 1}\\{ - 2}\\5\end{array}} \right)\).

Then, \({v_2} - {v_1} = \left( {\begin{array}{*{20}{c}}1\\3\\{ - 2}\end{array}} \right),\) and \({v_3} - {v_1} = \left( {\begin{array}{*{20}{c}}{ - 2}\\{ - 3}\\2\end{array}} \right)\).

Step 2: Use the cross product to compute n

(a)

\(\begin{array}{c}n = \left( {{v_2} - {v_1}} \right) \times \left( {{v_3} - {v_1}} \right)\\ = \left| {\begin{array}{*{20}{c}}1&{ - 2}&i\\3&{ - 3}&j\\{ - 2}&2&k\end{array}} \right|\\ = \left| {\begin{array}{*{20}{c}}3&{ - 3}\\{ - 2}&2\end{array}} \right|i - \left| {\begin{array}{*{20}{c}}1&{ - 2}\\{ - 2}&2\end{array}} \right|j + \left| {\begin{array}{*{20}{c}}1&{ - 2}\\3&{ - 3}\end{array}} \right|k\\ = 0i + 2j + 3k\end{array}\)

Thus, the normal vector is \(n = \left( {\begin{array}{*{20}{c}}0\\2\\3\end{array}} \right)\).

Step 3: Find a linear functional f and a real number d

(b)

Using part (a) to obtain the linear functional f as shown below:

\(\begin{array}{c}f\left( x \right) = n \cdot x\\ = \left( {\begin{array}{*{20}{c}}0&2&3\end{array}} \right)\left( {\begin{array}{*{20}{c}}{{x_1}}\\{{x_2}}\\{{x_3}}\end{array}} \right)\\f\left( x \right) = 2{x_2} + 3{x_3}\end{array}\)

Note that, \({v_i}\) in \(H = \left( {f:d} \right)\) such that, \(f\left( {{v_i}} \right) = d\) for \(i = 1,2,3\).

\(\begin{array}{c}d = f\left( {{v_1}} \right)\\ = f\left( {1,1,3} \right)\\ = 2\left( 1 \right) + 3\left( 3 \right)\\ = 2 + 9\\d = 11\end{array}\)

Thus, the linear function is \(f\left( x \right) = 2{x_2} + 3{x_3}\) , and the real number is \(d = 11\).

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