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Q6E

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Linear Algebra With Applications
Found in: Page 425
Linear Algebra With Applications

Linear Algebra With Applications

Book edition 5th
Author(s) Otto Bretscher
Pages 442 pages
ISBN 9780321796974

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Short Answer

Solve the nonlinear differential equations in Exercises 6through 11 using the method of separation of variables:Write the differential equation dxdt=fxasdxfx=dt and integrate both sides.

6.dxdt=1x,x(0)=1

The solution is x(t)=2t+1

See the step by step solution

Step by Step Solution

Step 1: Simplification for the differential equation

Consider the equation as follows:

dxdt=1x

Now, separate the variables as follows:

dxdt=1xxdx=dt

Integrating on both sides as follows:

xdx=dtxdx=dtx22=t+C

Substituting the initial condition as follows:

x22=t+C(1)22=0+C          {Qx(0)=1}12=C

Step 2 : Calculation of the solution

Now, substitute the value 12 for C in x22=t+C as follows:

x22=t+Cx22=t+12x22=2t2+12x22=2t+12

Simplify further as follows:

x22=2t+12x2=2t+1x=2t+1x(t)=2t+1

Hence, the solution for the differential equationdxdt=1x is x(t)=2t+1

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