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Q30E
Expert-verifiedState true or false, the linear transformation T (f) = f (4t - 3 ) from P to P is an isomorphism.
The statement is True
Consider the function T(f (t)) = f (4t - 3 ) from .
A function D is called a linear transformation on localid="1659425827307" if the function D satisfies the following property’s.
An invertible linear transformation is called isomorphism or dimension of domain and co-domain is not same then the function is not isomorphism.
Assume .
Substitute the value f ( 4t - 3 ) for T ( f (t) ) and g ( 4t - 3 ) for T ( f (t) ) in T ( f (t) ) +T ( f (t) ) as follows.
T ( f (t) ) +T ( f (t) ) =f (4t - 3) + g (4t - 3)
Now, simplify T ( { f + g } (t)) as follows.
T ( { f + g } (t)) = { f + g } ( 4t - 3)
T ( { f + g } (t)) = f ( 4t - 3) +g ( 4t - 3)
T ( { f + g } (t)) = T ( f(t) + T ( g (t))
Simplify the equation as follows.
As and , by the definition of linear transformation T is linear.
As is the basis element of P and the matrix corresponding to basis is upper triangular matrix.
Each row and column of upper triangular matrix is linearly independent.
Therefore, the rank (T) is n.
The Kernel (T) is defined as follows.
dim(T) = dim (Kernal (T)) + rank (T)
n = dim ( Kernel (T)) + 0
dim (Kernel (T)) = 0
Therefore, the dimension of is Kernel (T).
Theorem: Consider a linear transformation T defined from then the transformation T is an isomorphism if and only if Ker (T) = 0 where .
As the dimension of Kernel (T) is 0, by the theorem the function T is an isomorphism.
Hence, the statement is True.
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