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Q56E

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Linear Algebra With Applications
Found in: Page 185
Linear Algebra With Applications

Linear Algebra With Applications

Book edition 5th
Author(s) Otto Bretscher
Pages 442 pages
ISBN 9780321796974

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Short Answer

Find the image, kernel, rank, and nullity of the transformation T in T(f(t))=t(f'(t)) from P2 to P2.

The image contains of all the linear polynomial of the form 2at2+bt and the nullity is 1.

See the step by step solution

Step by Step Solution

Step1: Definition of rank of T

Consider the transformation as follows.

T:VW such that im(T)={T(f):fV}

If the image of T is finite dimensional, then dim(imT) is called the rank of T .

Step2: Explanation of the solution

Consider the linear transformation as follows.

T:P2P2 defined as T(f(t))=t(f'(t)).

Since,f(t)P2.

Consider the equation as follows.

f(t)=at2+bt+c

Simplify as follows.

Tft=tf't =tdfdtat2+bt+c =t2at+b =2at2+bt

Therefore, the image contains of all the second-degree polynomial of the form 2at2+bt.

Thus, the rank is 2 with the basis t,t2.

Step3: Definition of nullity of T

Consider the transformation as follows.

T:VW such that ker(T)={fV|T(f)=0}.

If the kernel of T is finite dimensional, then dim(kerT) is called the nullity of T

Consider a constant polynomial as follows.

T(f(t))=0

Then, f(t) is a constant polynomial

Therefore, the kernel consists of all the constant polynomial with the basis {1} .

The nullity is 1.

Hence, the image contains of all the linear polynomial of the form 2at2+bt and the rank is 2 whereas the kernel contains all the constant polynomial and the nullity is 1.

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