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Q57E

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Linear Algebra With Applications
Found in: Page 57
Linear Algebra With Applications

Linear Algebra With Applications

Book edition 5th
Author(s) Otto Bretscher
Pages 442 pages
ISBN 9780321796974

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Short Answer

Some parking meters in downtown Geneva, Switzerland, accept 2 Franc and 5 Franc coins.

a. A parking officer collects 51 coins worth 144 Francs. How many coins are there of each kind?

b. Find the matrix A that transforms the vector

[number of 2 Franc coinsnumber of 5 Franc coins]

into the vector

[total value of coinstotal number of coins]

c. Is the matrix A in part (b) invertible? If so, find the inverse (use Exercise 13). Use the result to check your answer in part (a).

a. There are 37coins of SFr2 and 14coins of SFr5.

b. The matrix Ais A=2511.

c. The matrix A is invertible and the inverse is A-1=-135313-23,

See the step by step solution

Step by Step Solution

Step by Step Explanation: Step 1: Compute the masses of alloy.

(a)

Consider the different types of coins in terms of equations.

2x+5y=144x+y=51

Represent the equations in terms of matrix and compute the reduced row-echelon form of the matrix.

251441151=251440-32-21=10370114

The number of coins is:

SFr2=37coins,SFr5=14coins

Step 2: Compute the matrix.

(b)

The matrix that represents the different kinds of coins is,

[number of 2 Franc coinsnumber of 5 Franc coins]=[2x5y]

Consider the mass and volume of alloy in terms of equations.

2x+5y=144x+y=51

Represent the equations in terms of matrix

2511xy=14451

The required matrix is,

A=2511

The matrix that transforms the different types of coins into the total number and volume of the coins is,

[total value of coinstotal number of coins]=[2511]

Step 3: Check for invertibility and compute the inverse of the matrix.

(c)

Check for the invertible matrix

A=2×1-1×50

As the determinant of the matrix is nonzero, thus, it is invertible.

The inverse of the matrix is,

role="math" localid="1659777378747" A=2511A-1=12×1-1×51-5-12A-1=-131-5-12A-1=[-135313-23]

Hence, the matrix A is invertible and the inverse is A-1=[-135313-23],

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