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Q36E

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Linear Algebra With Applications
Found in: Page 120
Linear Algebra With Applications

Linear Algebra With Applications

Book edition 5th
Author(s) Otto Bretscher
Pages 442 pages
ISBN 9780321796974

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Short Answer

Consider a nonzero vector υin 3 . Using a geometric argument, describe the kernel of the linear transformation Tfrom 3to 3 given by,

T(x)=υ×x

See Definition A.9 in the Appendix.

The kernel is a line in space spanned by vector υ

See the step by step solution

Step by Step Solution

Step by Step Solution:  Step 1: To define kernel of linear transformation

The kernel of linear transformation is defined as follows:

The kernel of a linear transformation Tx=Ax from m to n consists of all zeros of the transformation, i.e., the solutions of the equations Tx=Ax=0.

It is denoted by kerT or kerA

The definition A.9 cross product in 3is given as follows:

The cross product υ×ω of two vectors role="math" localid="1659527572946" υand ω in 3 is the vector in 3 with three properties as follows:

  1. υ×ωis orthogonal to both υandω.
  2. υ×ω=υsinθω, where θ is angle between υand ω with 0θπ.
  3. The direction of υ×ω follows the right-hand rule.

We have given the linear transformation T:33 defined by Tx=υ×x,

Step 2: To describe the kernel of the linear transformation

With the reference of definition in step 1, we have,

Tx=υ×x=0^Ux=λυ,λ^IR is any scalar, which means that the cross product is zero.

This implies that kernel is a line in space spanned by vector υ

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