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Q39E

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Linear Algebra With Applications
Found in: Page 132
Linear Algebra With Applications

Linear Algebra With Applications

Book edition 5th
Author(s) Otto Bretscher
Pages 442 pages
ISBN 9780321796974

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Short Answer

Consider some linearly independent vectors in and a vector v1,v2,...vm, in n and a vectorv in n that is not contained in the span v1,v2,...vm of . Are the vectors v1,v2,....vm,v necessarily linearly independent?

If there are some linearly independent vectors in and a vector v1,v2,..vm, in nand a vector v innthat is not contained in the span of v1,v2,...vm then the vectors are necessarily linearly independent.

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Step by Step Solution

Step 1:   Linear Relations

Consider the vectors v1,v2,...vm in . An equation of the form

a1v1+a2v2+...+amvm=0 (1)

is called a (linear) relation among the vectors v1,v2,...v3. There is always the trivial relation, with a1=0=a2=...=am. Nontrivial relations (where at least one coefficient ai is nonzero) may or may not exist among the vectors v1,v2,...vm. .

Step 2: To prove the vectors v→1,v→2,...v→m,v→  are linearly independent

Since the vector v in nis not contained in the span of v1,v2,...vm,. Therefore

va1v1,+a2v2+...+amvm, for ai0 . (2)

Now multiply the equation (2) by role="math" localid="1659416449027" b and b0 from left ,then we have

bvba1v1+ba2v2+...+bamvm (3)

Now subtract both sides by bv, , we get

role="math" localid="1659416709972" 0ba1v1+ba2v2+...bamvm-bv (4)

Since b0bai0, so the right hand side of equation (4) will be zero if and only if bai=0.

Hence, the vectors v1,v2,...vmv are linearly independent.

Step 3: Final Answer

If there are some linearly independent vectors in v1,v2,...vminn and a vector n in that is not contained in the span v1,v2,...vm of then the vectors v1,v2,...vm,v are necessarily linearly independent.

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