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Q49E

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Linear Algebra With Applications
Found in: Page 132
Linear Algebra With Applications

Linear Algebra With Applications

Book edition 5th
Author(s) Otto Bretscher
Pages 442 pages
ISBN 9780321796974

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Short Answer

Express the line L in 3 spanned by the vector [111] as the image of a matrix Aand as the kernel of a matrix B.

Matrix A

A=111

Matrix B

B=112110

See the step by step solution

Step by Step Solution

Step 1: Spanned by vector

For a line to be an image of a matrix A it has to be spanned by column vectors of A, and since it is spanned by a vector already we'll use it as a column vector

A=111

For a line to be a kernel of matrix B the equality must be correct

B=111=0

Step 2: Choose vector that gives 0 in dot product

Since we have no other conditions we can choose any vector that gives 0 in dot product with

v=111

We choose vector

w=112

But we can construct another vector that gives 0 in dot product with w so our matrix is not complete, we know that kernel of must form a plane.

So we find another vector k that is non collinear with w and it's dot product with v is 0 let's say

k=110

Step 3: Construct matrix B

Now we have two non collinear vectors so they span a plane and now we construct matrix B

B=112110

Step 4: The final answer

Matrix A

A=111

Matrix B

B=112110

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