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Q17E

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Linear Algebra With Applications
Found in: Page 400
Linear Algebra With Applications

Linear Algebra With Applications

Book edition 5th
Author(s) Otto Bretscher
Pages 442 pages
ISBN 9780321796974

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Short Answer

Sketch the curves defined in Exercises 15 through 20. In each case, draw and label the principal axes, label the intercepts of the curve with the principal axes, and give the formula of the curve in the coordinate system defined by the principal axes.

17. 3x12+4x1x2=1

v1=1521 and v2=15-12

See the step by step solution

Step by Step Solution

Step 1: Given Information:

3x12+4x1x2=1

Step 2: To Find the Eigen values:

qx1,x2=3x12+4x1x2=1=x1x23x1+2x22x1

Split the term 4x1x2 equally between the two components. Therefore

qx=x×Ax , where A=3220

To determine the eigen values of the matrix A

det(A-λl)=0 3-λ220-λ=03-λ0-λ-22=0λ2-3λ-4=0λ-4λ+1=0

The eigen values are λ1=4 and λ2=-1

To find the eigen vectors are λ1=4

A-4Ix~=03-4220-4x1x2=0-122-4x1x2=0

Apply Row operation R2R2+2R1

-1200x1x2=0

The first row implies x1=2x2,x2=1,x1=2,λ1=4

u1=21

Orthonormal eigen basis simply by dividing the given eigen vector by its length

v1=1u1u1=1521

When λ2=-1

A+lx=0 3+1220+1x1x2=04221x1x2=0

Apply row operation R22R2-R1

4200x1x2=0

First row implies that x1=-12x2,x2=2,x1=-1,λ2=-1

u2=-12

Orthonormal eigen basis simply by dividing the given eigen vector by its length

v2=1u2u2=15-124c12-c12=1

v1=1521 and v2=15-12

Step 3: To Find the graph of the axes:

The graph of the coordinate axes is

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