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Q33E

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Linear Algebra With Applications
Found in: Page 401
Linear Algebra With Applications

Linear Algebra With Applications

Book edition 5th
Author(s) Otto Bretscher
Pages 442 pages
ISBN 9780321796974

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Short Answer

Find the Cholesky factorization (discussed in Exercise 32) for

A=[8225]

The Cholesky factorization is

8-2-25=220-1/23/222-1/203/2

See the step by step solution

Step by Step Solution

Step 1: Given Information:

A=8-2-25

Step 2: Estimating the Cholesky factorization:

We can deduce from Exercise 32 that 2×2 positive definite matrix exists.

A=abbc

The form A=LLT is a Cholesky factorization. Where,

L=a0b/aac-b2/a

is a positive diagonal matrix with lower triangular entries. The structure of the matrix

A=8-2-25

A1=8>0and A2=40-4=36>0 are positive definite Thus,

L=220-1/23/2.

A's Cholesky factorization is as follows:

LLT=220-1/23/22/2-1/203/2=8-2-25=A

Step 3: Determining the Result:

The Cholesky factorization is

8-2-25=220-1/23/222-1/203/2

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