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Q26.

Expert-verifiedFound in: Page 696

Book edition
Common Core Edition

Author(s)
Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff

Pages
183 pages

ISBN
9780547587776

**Solve the equation by first clearing the fractions.**

**$\frac{7}{10}x-\frac{1}{5}=\frac{3}{8}$**

The solution is $x=\frac{23}{28}$.

The equation is$\frac{7}{10}x-\frac{1}{5}=\frac{3}{8}$.

**First, find out the LCD and then the LCD has to substitute each side.**

$\begin{array}{c}\frac{7}{10}x-\frac{1}{5}=\frac{3}{8}\\ 40\left(\frac{7}{10}x-\frac{1}{5}\right)=40\left(\frac{3}{8}\right)\\ 40\left(\frac{7}{10}x\right)-40\left(\frac{1}{5}\right)=40\left(\frac{3}{8}\right)\\ 28x-8=15\end{array}$

On further simplification,

$\begin{array}{c}28x=15+8\\ 28x=23\\ x=\frac{23}{28}\end{array}$

The solution of the given equation is $x=\frac{23}{28}$.

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