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Q40.

Expert-verifiedFound in: Page 691

Book edition
Common Core Edition

Author(s)
Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff

Pages
183 pages

ISBN
9780547587776

**Solve the equation. Check your solution.**

** **

**$10-3x=37$**

The solution of equation is **-9.**

The given equation is $10-3x=37$.

Solve the given equation by shifting the constant from left hand side to right hand side.

$\begin{array}{c}10-3x=37\\ -3x=37-10\\ -3x=27\end{array}$

Divide the equation by -3.

$\begin{array}{c}\frac{-3x}{-3}=\frac{27}{-3}\\ x=-9\end{array}$

Hence, the value of *x* after solving the equation is -9.

Substitute -9 for *x *in* *the given equation

$\begin{array}{c}10-3\left(-9\right)=37\\ 10+27=37\\ 37=37\end{array}$

Since left side is equal to right side. Therefor the solution of the equation is -9

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