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Q12.

Expert-verifiedFound in: Page 400

Book edition
Common Core Edition

Author(s)
Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff

Pages
183 pages

ISBN
9780547587776

**Solve the inequality. Graph the solution.**

The solution for our given inequality would be $m>27$ and in interval notation $\left(27,\infty \right)$.

An equation: $m-6>21$

To solve an inequality, we use opposite operations as we use to solve an equation. When we divide or multiply both sides of an inequality by any negative number, it reverses the inequality.

We will solve our given inequality using opposite operations as shown below:

$\begin{array}{c}m-6>21\text{(Given inequality)}\\ m-6+6>21+6(\text{Adding}6\text{ on both sides)}\\ m>27\end{array}$

Therefore, the solution for our given inequality would be all values of *m *greater than 27. The solution of our given inequality in interval notation would be $(27,\infty )$.

Since 27 is not a solution of our given inequality, so we will have an open dot at $m=27$. Upon graphing solution of our given inequality, we will get:

The solution for our given inequality would be $m>27$ and in interval notation $(27,\infty )$.

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