StudySmarter AI is coming soon!

- :00Days
- :00Hours
- :00Mins
- 00Seconds

A new era for learning is coming soonSign up for free

Suggested languages for you:

Americas

Europe

Q.18

Expert-verifiedFound in: Page 551

Book edition
Common Core Edition

Author(s)
Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff

Pages
183 pages

ISBN
9780547587776

**The height of trapezoid is 2 feet. One of the bases is three times the height, and the other base is four times the height. Find the area of the trapezoid. **

The area of the trapezoid is$14{\text{feet}}^{2}$.

The height is 2 feet and one bases is three times to height, and other base is four times to height.

The formula of area of trapezoid is defined as,

$\text{Area}=\frac{1}{2}\times \left(\text{Sum of parallel sides}\right)\times \text{Height}$

Find the both base by using height.

$\begin{array}{c}{b}_{1}=3\times \text{height}\\ =3\left(2\right)\\ =6\text{feet}\end{array}$

And,

$\begin{array}{c}{b}_{2}=4\times \text{height}\\ =4\left(2\right)\\ =8\text{feet}\end{array}$

Substitute the values in the area formula.

$\begin{array}{c}\text{Area}=\frac{1}{2}\left(6+8\right)\times 2\\ =\frac{1}{2}\times 14\times 2\\ =14{\text{feet}}^{2}\end{array}$

Therefore, the required area is$14{\text{feet}}^{2}$.

94% of StudySmarter users get better grades.

Sign up for free