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Q36.

Expert-verifiedFound in: Page 127

Book edition
Common Core Edition

Author(s)
Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff

Pages
183 pages

ISBN
9780547587776

**Geometry Find the value of x for the given triangle, rectangle or square.**

**Perimeter = 32 units**

The value of x is 2.

Perimeter = 32 units, length is x unit and width is $2x+10$.

We have to find the value of the x for the given rectangle.

The equation of the perimeter will be $2\left[x+\left(2x+10\right)\right]=40$

$\begin{array}{l}2\left[x+\left(2x+10\right)\right]=32\\ 2\left[x+2x+10\right]=32\text{}\left[\text{combine like terms}\right]\\ 2\left(3x+10\right)=32\text{}\left[\text{distributive property}\right]\text{}\\ 6x+20=32\\ 6x+20-20=32-20\text{}\left[\text{subtract 20 from each side}\right]\\ 6x=12\text{}\\ 6x\xf76=12\xf76\text{}\left[\text{divide each side by 6}\right]\\ x=2\end{array}$

Hence, the required value of x is 2.

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