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Q5.

Expert-verifiedFound in: Page 120

Book edition
Common Core Edition

Author(s)
Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff

Pages
183 pages

ISBN
9780547587776

**How is solving $3\mathrm{x}-7=-5$different from solving $3\mathrm{x}+7=-5$?**

** **

Solving equation $3x-7=-5$ requires addition of 7 to both sides of the equation first and solving $3x+7=-5$ requires subtraction of 7 from both sides of the equation first.

Solve the equation $3x-7=-5$.

$\begin{array}{l}3x-7=-5\\ 3x=-5+7\\ 3x=2\\ x=\frac{2}{3}\end{array}$

The solution of the equation is$x=\frac{2}{3}$.

Write the second equation and solve it.

$\begin{array}{l}3x+7=-5\\ 3x=-5-7\\ 3x=-12\\ x=\frac{-12}{3}\\ x=-4\end{array}$

Therefore, the solution of the equation is $x=-4$.

To solve the $3x-7=-5$, one needs to add 7 to both sides of the equation first and for solving $3x+7=-5$, one needs to subtract 7 from both sides of the equation.

Thus, solving equation $3x-7=-5$ requires addition of 7 to both sides of the equation first and solving $3x+7=-5$requires subtraction of 7 from both sides of the equation first.

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