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Q6.

Expert-verifiedFound in: Page 127

Book edition
Common Core Edition

Author(s)
Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff

Pages
183 pages

ISBN
9780547587776

**Solve the equation. Check your solution.**

The solution for the equation $3(x+1)=6$ is$x=1$ .

Write the original equation and separate the variable and constants.

$\begin{array}{c}3\left(x+1\right)=6\\ 3x+3=6\\ 3x+3-3=6-3\\ 3x=3\end{array}$

Now, divide both sides of the equation by 1.

$\begin{array}{c}\frac{3x}{3}=\frac{3}{3}\\ x=1\end{array}$

Therefore, the solution of the equation is$x=1$ .

To check the solution, write the original equation and substitute the value of *x*.

$3(x+1)=6$

** **Now, substitute$x=1$and check the result.

$\begin{array}{c}3(1+1)=6\\ 3\left(2\right)=6\\ 6=6\end{array}$

As the left-hand side is equal to right hand side, this signifies that the solution is correct.

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