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Q13.

Expert-verified
Found in: Page 220

### Pre-algebra

Book edition Common Core Edition
Author(s) Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff
Pages 183 pages
ISBN 9780547587776

# Use the LCD to determine which fraction is greater. $\frac{13}{15},\frac{11}{18}$

The fraction $\frac{\mathbf{13}}{\mathbf{15}}$ is greater than fraction $\frac{\mathbf{11}}{\mathbf{18}}$ .

See the step by step solution

## Step 1. Given information

The fraction $\frac{13}{15},\frac{11}{18}$ .

## Step 2. Calculation

To evaluate the greater fraction in $\frac{13}{15},\frac{11}{18}$, it is needed to calculate the least common multiple of 15,18.

Therefore, the least common multiple of 15, 18 is 90 and this will be least common denominator of fraction $\frac{13}{15},\frac{11}{18}$.

Make equivalent fraction of each fraction by least common denominator.

$\begin{array}{l}\frac{13}{15}=\frac{13×6}{15×6}\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}};\frac{11}{18}=\frac{11×5}{18×5}\\ \frac{13}{15}=\frac{78}{90}\text{​​​​​​​\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}};\frac{11}{18}=\frac{55}{90}\end{array}$

As the equivalent fractional of $\frac{13}{15},\frac{11}{18}$have same denominator so compare the numerator

$78>55$

$\frac{13}{15}>\frac{11}{18}$

Hence, the fraction $\frac{13}{15}$ is greater than fraction $\frac{11}{18}$