Suggested languages for you:

Americas

Europe

Q 3.

Expert-verified
Found in: Page 643

### Precalculus Enhanced with Graphing Utilities

Book edition 6th
Author(s) Sullivan
Pages 1200 pages
ISBN 9780321795465

# Use the Square Root Method to find the real solutions of ${\left(x+4\right)}^{2}=9$.

Real solution of ${\left(x+4\right)}^{2}=9$ is x = -1 and $x=-7$.

See the step by step solution

## Step 1. Given information.

We have given equation is,

${\left(x+4\right)}^{2}=9$

## Step 2. Concept used.

If ${a}^{2}=bthena=\sqrt{b}anda=-\sqrt{b}$.

## Step 3. Explanation.

We have given,

${\left(x+4\right)}^{2}=9$

Using square root method,

localid="1646649530505" $\left(x+4\right)=\sqrt{9}and\left(x+4\right)=-\sqrt{9}$

Solving both equations for x,

$\left(x+4\right)=3and\left(x+4\right)=-3\phantom{\rule{0ex}{0ex}}⇒x=3-4andx=-3-4\phantom{\rule{0ex}{0ex}}⇒x=-1andx=-7$

## Step 4. Conclusion.

Hence, the real solution for ${\left(x+4\right)}^{2}=9$ is

$x=-1$ and $x=-7$