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Q. 38

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Precalculus Enhanced with Graphing Utilities
Found in: Page 644
Precalculus Enhanced with Graphing Utilities

Precalculus Enhanced with Graphing Utilities

Book edition 6th
Author(s) Sullivan
Pages 1200 pages
ISBN 9780321795465

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Short Answer

Find the vertex, focus, and directrix of each parabola. Graph the equation by hand. Verify your graph using a graphing utility.

y2=8x

The vertex is 0,0 focus is 2,0 and directrix is x=-2 . The graph of the given equation is shown below .

See the step by step solution

Step by Step Solution

Step 1. Given information .

Consider the given equation y2=8x .

Step 2. Analyze the equation .

The standard form of parabola is y2=4ax .

Compare the equation with standard form.

y2=4axy2=8x4a=8a=2

Further simplify .

Since a=2 the vertex is 0,0 ,the focus is a,0=2,0 and the directrix is x=-a, x=-2

Step[ 3. Plot the graph .

The graph of the equation y2=8x using graphing utility is shown below .

Here V is the vertex , F is the focus and line x=-2 represents the directrix of the parabola .

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