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Q 60.

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Precalculus Enhanced with Graphing Utilities
Found in: Page 655
Precalculus Enhanced with Graphing Utilities

Precalculus Enhanced with Graphing Utilities

Book edition 6th
Author(s) Sullivan
Pages 1200 pages
ISBN 9780321795465

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Short Answer

Find an equation for each ellipse. Graph the equation by hand.

Vertices at (2,5) and (2,-1):c=2

The equation of the ellipse is (x-2)25+(y-2)29=1and graph of the ellipse is

See the step by step solution

Step by Step Solution

Step 1. Given information.  

Vertices at (2,5) and (2,-1): c=2

The vertices lies on the line x=2, thus the major axis is parallel to the y-axis.

The center is at the mid point of the vertices (2,2).

The distance of the center from one of the foci is c=2.

The distance of the center from one of the vertices is a=3.

Step 2. The equation of ellipse.  

Substitute a=3 and c=2 in b2=a2-c2 we get.

b2=a2-c2b2=9-4b2=5

Substituting the values of a2 and b2 in the equation of the ellipse we get.

(x-2)25+(y-2)29=1

Step 3 .Graph of the ellipse .  

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