Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration

Q 62.

Expert-verified
Precalculus Enhanced with Graphing Utilities
Found in: Page 655
Precalculus Enhanced with Graphing Utilities

Precalculus Enhanced with Graphing Utilities

Book edition 6th
Author(s) Sullivan
Pages 1200 pages
ISBN 9780321795465

Answers without the blur.

Just sign up for free and you're in.

Illustration

Short Answer

Find an equation for each ellipse. Graph the equation by hand.

Center at (1,2): focus at (1,4): contains the point (2,2)

The equation of the ellipse is (x-1)21+(y-2)25=1and graph of the ellipse is

See the step by step solution

Step by Step Solution

Step 1 . Given information. 

Center at (1,2): focus at (1,4) contains the point(2,2).

Since the center and the focus lie on the line x=1, thus the major axis is parallel to the y-axis.

The distance of the center from one of the foci is c=2

Since, the point (2,2) lies on the ellipse

(2-1)2b2+(2-2)2a2=1b2=1

Step 2. The equation of ellipse. 

Substitute c=2 and a=1 we get.

b2=a2-c2a2=b2+c2a2=1+4a2=5

The equation of the ellipse is (x-1)21+(y-2)25=1

Step 3. Graph of the ellipse .    

Recommended explanations on Math Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.