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Q 70.

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Precalculus Enhanced with Graphing Utilities
Found in: Page 655
Precalculus Enhanced with Graphing Utilities

Precalculus Enhanced with Graphing Utilities

Book edition 6th
Author(s) Sullivan
Pages 1200 pages
ISBN 9780321795465

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Short Answer

Semi elliptical Arch Bridge The arch of a bridge is a semi ellipse with a horizontal major axis. The span is 30 feet, and the top of the arch is 10 feet above the major axis. The roadway is horizontal and is 2 feet above the top of the arch. Find the vertical distance from the roadway to the arch at 5-foot intervals along the roadway.

The vertical distance from the roadway to arch at 5 foot intervals are 2.57feet ,4.54 feet and 12 feet.

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Step by Step Solution

Step 1. Given information.

The major axis of the arch is parallel to the x-axis. since the span of the arch is 30 feet, this means

a=302a=15

The top of the arch is 10 feet above the major axis.This means b=10.

The road ways lies 2 feet above top of the arch.Thus, the coordinates of the center are (0,-12).

Step 2. The equation of the ellipse and graph of the arch.

The equation of the ellipse is (x-0)2225+(y+12)2100=1

The graph of the arch is

Step 3. Vertical distance from roadway to arch.

Now, putting x=5 in the equation of ellipse

role="math" localid="1646806151750" 25225+(y+12)2100=1(y+12)2=8009 y=±2023-12y=-2.57,-21.42

We have considered only the upper semi- ellipse constituting the arch.

Putting x=10 in the equation we get.

role="math" localid="1646806607812" 100225+(y+12)2100=1(y+12)2=5009y=±1053-12y=-4.54

For x=-15 and x=15 y=-12

Thus, the vertical distances from the roadway to arch at 5 foot intervals are 2.57feet, 4.54 feet and 12 feet.

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