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Q. 44

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Found in: Page 865

### Precalculus Enhanced with Graphing Utilities

Book edition 6th
Author(s) Sullivan
Pages 1200 pages
ISBN 9780321795465

# Two fair dice are rolled.Determine the probability that the sum of the two dice is 12.

The probability is $\frac{1}{36}$

See the step by step solution

## Step 1. Given Information

The given statement is the sum of the two dice is 12.

## Step 2. Calculation

The probability of an event is given by the number of ways the event can occur divided by the total number of outcomes in the sample space.

When two dice are rolled sample space is given by $n\left(S\right)=36$ that is total number of elements in the sample space.

Let E represent the event 'the sum of two dice is 12' that is $n\left(E\right)=1$

On substituting the values in the formula, we get,

$P=\frac{n\left(E\right)}{n\left(S\right)}\phantom{\rule{0ex}{0ex}}=\frac{1}{36}$