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Q. 44

Expert-verifiedFound in: Page 865

Book edition
6th

Author(s)
Sullivan

Pages
1200 pages

ISBN
9780321795465

Two fair dice are rolled.

Determine the probability that the sum of the two dice is 12.

The probability is $\frac{1}{36}$

The given statement is the sum of the two dice is 12.

The probability of an event is given by the number of ways the event can occur divided by the total number of outcomes in the sample space.

When two dice are rolled sample space is given by $n\left(S\right)=36$ that is total number of elements in the sample space.

Let E represent the event 'the sum of two dice is 12' that is $n\left(E\right)=1$

On substituting the values in the formula, we get,

$P=\frac{n\left(E\right)}{n\left(S\right)}\phantom{\rule{0ex}{0ex}}=\frac{1}{36}$

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