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Q. 63

Expert-verifiedFound in: Page 866

Book edition
6th

Author(s)
Sullivan

Pages
1200 pages

ISBN
9780321795465

Problems 63–66 are based on a consumer survey of annual incomes in 100 households. The following table gives the data.

What is the probability that a household has an annual income of $30,000 or more?

The probability is $\frac{3}{10}$

The given table is

The number of households having an annual income of $30,000 or more is $n\left(E\right)=20+10=30$

The sample space consists of households, the number of households are $n\left(S\right)=5+35++30+20+10=100$

Substitute the values in the formula to find the required probability,

$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}\phantom{\rule{0ex}{0ex}}=\frac{30}{100}\phantom{\rule{0ex}{0ex}}=\frac{3}{10}$

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