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Q. 63

Expert-verified
Found in: Page 866

### Precalculus Enhanced with Graphing Utilities

Book edition 6th
Author(s) Sullivan
Pages 1200 pages
ISBN 9780321795465

# Problems 63–66 are based on a consumer survey of annual incomes in 100 households. The following table gives the data.What is the probability that a household has an annual income of $30,000 or more? The probability is $\frac{3}{10}$ See the step by step solution ### Step by Step Solution ## Step 1. Given Information The given table is ## Step 2. Calculation The number of households having an annual income of$30,000 or more is $n\left(E\right)=20+10=30$

The sample space consists of households, the number of households are $n\left(S\right)=5+35++30+20+10=100$

Substitute the values in the formula to find the required probability,

$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}\phantom{\rule{0ex}{0ex}}=\frac{30}{100}\phantom{\rule{0ex}{0ex}}=\frac{3}{10}$