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Q. 68

Expert-verifiedFound in: Page 284

Book edition
6th

Author(s)
Sullivan

Pages
1200 pages

ISBN
9780321795465

Solve the equation ${5}^{x+3}=\frac{1}{5}$

and verify your results using a graphing utility.

Required solution set is {-4}.

${5}^{x+3}=\frac{1}{5}$

${5}^{x+3}=\frac{1}{5}\phantom{\rule{0ex}{0ex}}{5}^{x+3}={5}^{-1}if{a}^{u}={a}^{v}thenu=v\phantom{\rule{0ex}{0ex}}x+3=-1\phantom{\rule{0ex}{0ex}}x=-4$

Graph $y={5}^{x+3}$and y =1/5 intersect at (-4,0.2)

Hence the required solution set is {-4}.

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