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Q. 81

Expert-verifiedFound in: Page 284

Book edition
6th

Author(s)
Sullivan

Pages
1200 pages

ISBN
9780321795465

If ${4}^{x}=7$ , what does ${4}^{-2x}$ equal?

The value of ${4}^{-2x}$ is $\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$49$}\right.$.

Given :

${4}^{x}=7$

We have to find ${4}^{-2x}$

${4}^{-2x}={({4}^{x})}^{-2}$

${\left({4}^{x}\right)}^{-2}={\left(7\right)}^{-2}=\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{${7}^{2}$}\right.=\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$49$}\right.$

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