Book edition 6th

Author(s) Sullivan

Pages 1200 pages

ISBN 9780321795465

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Short Answer

In Problem 17-36, solve each equation algebraically. Verify your solution using a graphing utility.
$\frac{x + 1}{3} + \frac{x + 2}{7} = 5$

The required solution is $x = \frac{46}{5}$ . The graph of the solution is given below:

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1. Given information.

We have:

$\frac{x + 1}{3} + \frac{x + 2}{7} = 5$

Step 2. Solve the equation algebraically.

The equation is $\frac{x + 1}{3} + \frac{x + 2}{7} = 5$ .

Find the least common multiplier of $3, 7$ : $21$

Multiply by LCM (Least common multiple) to both sides of the equation.

$\frac{x + 1}{3} \cdot 21 + \frac{x + 2}{7} \cdot 21 = 5 \cdot 21 7 (x + 1) + 3 (x + 2) = 105 7 x + 7 + 3 x + 6 = 105 10 x + 13 = 105$

Subtract $13$ to both sides:

$10 x + 13 - 13 = 105 - 13 10 x = 92 \frac{10 x}{10} = \frac{92}{10} x = \frac{46}{5}$

Step 3. Verify the solution using a graphing utility.

The solution of the equation is $x = \frac{46}{5}$ .

Draw the graph of the equation $\frac{x + 1}{3} + \frac{x + 2}{7} = 5$ using the graphing utility:

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Precalculus Enhanced with Graphing Utilities

Answers without the blur.

Short Answer

In Problem 17-36, solve each equation algebraically. Verify your solution using a graphing utility.
$\frac{x + 1}{3} + \frac{x + 2}{7} = 5$

Step by Step Solution

Step 1. Given information.

Step 2. Solve the equation algebraically.

Step 3. Verify the solution using a graphing utility.

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Precalculus Enhanced with Graphing Utilities

Answers without the blur.

Short Answer

In Problem 17-36, solve each equation algebraically. Verify your solution using a graphing utility.x+13 +x+27=5

Step by Step Solution

Step 1. Given information.

Step 2. Solve the equation algebraically.

Step 3. Verify the solution using a graphing utility.

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In Problem 17-36, solve each equation algebraically. Verify your solution using a graphing utility.
$\frac{x + 1}{3} + \frac{x + 2}{7} = 5$