Book edition 6th

Author(s) Sullivan

Pages 1200 pages

ISBN 9780321795465

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Short Answer

Use the converse of the Pythagorean Theorem to show that a triangle whose sides are of lengths 11, 60, and 61 is a right triangle.

The given triangle is a right triangle because ${(61)}^{2} = {(11)}^{2} + {(60)}^{2}$ .

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1. Given information.

The lengths of a triangle are 11, 60 and 61.

Step 2. Show that the triangle is a right triangle.

Converse of the Pythagorean Theorem: In a triangle, if the square of the length of one side equals the sum of the squares of the lengths of the other two sides, the triangle is a right triangle.

The square of the largest side is:

${(61)}^{2} = 3721$

The sum of squares of the other two sides is:

$\begin{array}{rcl} {(60)}^{2} + {(11)}^{2} & = & 3600 + 121 \\ = & 3721 \end{array}$

Step 3. Conclusion.

The given triangle is a right triangle because ${(61)}^{2} = {(11)}^{2} + {(60)}^{2}$ .

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Precalculus Enhanced with Graphing Utilities

Answers without the blur.

Short Answer

Use the converse of the Pythagorean Theorem to show that a triangle whose sides are of lengths 11, 60, and 61 is a right triangle.

Step by Step Solution

Step 1. Given information.

Step 2. Show that the triangle is a right triangle.

Step 3. Conclusion.

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Precalculus Enhanced with Graphing Utilities

Answers without the blur.

Short Answer

Use the converse of the Pythagorean Theorem to show that a triangle whose sides are of lengths 11, 60, and 61 is a right triangle.

Step by Step Solution

Step 1. Given information.

Step 2. Show that the triangle is a right triangle.

Step 3. Conclusion.

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