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Expert-verified Found in: Page 155 ### Precalculus Enhanced with Graphing Utilities

Book edition 6th
Author(s) Sullivan
Pages 1200 pages
ISBN 9780321795465 # The $x$-coordinate of the vertex of $f\left(x\right)=a{x}^{2}+bx+c,a\ne 0$, is ________.

The $x$-coordinate of the vertex of $f\left(x\right)=a{x}^{2}+bx+c,a\ne 0$, is $-\frac{b}{2a}$.

See the step by step solution

## Step 1. Given information.

The given statement is:

The $x$-coordinate of the vertex of $f\left(x\right)=a{x}^{2}+bx+c,a\ne 0$, is ________.

## Step 2. Determine the missing term for the blank.

The vertex of a quadratic function $f\left(x\right)=a{x}^{2}+bx+c,a\ne 0$ is:

$Vertex=\left(-\frac{b}{2a},f\left(-\frac{b}{2a}\right)\right)$

## Step 3. Conclusion.

The $x$-coordinate of the vertex of $f\left(x\right)=a{x}^{2}+bx+c,a\ne 0$, is $-\frac{b}{2a}$. ### Want to see more solutions like these? 