Short Answer

The standard equation of a circle with center at $(- 2, 5)$ and radius $3$ is ______ .

The standard equation of a circle with center at $(- 2, 5)$ and radius $3$ is ${(x + 2)}^{2} + {(y - 5)}^{2} = 9 .$

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Step 1. Given Information

The given center of a circle is $(- 2, 5)$ and radius is $3 .$

Step 2. Filling the blank

The standard equation of a circle with center $(h, k),$ and radius $r$ is ${(x - h)}^{2} + {(y - k)}^{2} = r^{2} .$

So, the standard equation of a circle with center at $(- 2, 5)$ and radius $3$ is role="math" localid="1646719972363" ${(x + 2)}^{2} + {(y - 5)}^{2} = 3^{2} {(x + 2)}^{2} + {(y - 5)}^{2} = 9$

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Precalculus Enhanced with Graphing Utilities

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Short Answer

The standard equation of a circle with center at $(- 2, 5)$ and radius $3$ is ______ .

Step by Step Solution

Step 1. Given Information

Step 2. Filling the blank

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Precalculus Enhanced with Graphing Utilities

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Short Answer

The standard equation of a circle with center at -2,5 and radius 3 is ______ .

Step by Step Solution

Step 1. Given Information

Step 2. Filling the blank

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The standard equation of a circle with center at $(- 2, 5)$ and radius $3$ is ______ .