Short Answer

In Problems 71-82, find the sum of each sequence.
${\sum (-}_{k = 1}^{24} k)$

The sum of this sequence is (-300).

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1. Write the given information.

The sum of sequence: ${\sum (-}_{k = 1}^{24} k)$ .

Step 2. Use the formula for sum of sequence of n real numbers.

The formula for summation is: ${\sum k}_{k = 1}^{n} = 1 + 2 + . . . + n \Rightarrow {\sum k}_{k = 1}^{n} = \frac{n (n + 1)}{2}$

Step 3. Use the formula with c = (-k) and n=24.

Using the formula gives:

${\sum (- k)}_{k = 1}^{24} = {- \sum (k)}_{k = 1}^{24} \Rightarrow {- \sum (k)}_{k = 1}^{24} = - \frac{24 \times (24 + 1)}{2} \Rightarrow {- \sum k}_{k = 1}^{24} = - \frac{24 \times (25)}{2} \Rightarrow {- \sum k}_{k = 1}^{24} = - 300$

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Precalculus Enhanced with Graphing Utilities

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Short Answer

In Problems 71-82, find the sum of each sequence.
${\sum (-}_{k = 1}^{24} k)$

Step by Step Solution

Step 1. Write the given information.

Step 2. Use the formula for sum of sequence of n real numbers.

Step 3. Use the formula with c = (-k) and n=24.

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Precalculus Enhanced with Graphing Utilities

Answers without the blur.

Short Answer

In Problems 71-82, find the sum of each sequence.∑(-k=124k)

Step by Step Solution

Step 1. Write the given information.

Step 2. Use the formula for sum of sequence of n real numbers.

Step 3. Use the formula with c = (-k) and n=24.

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In Problems 71-82, find the sum of each sequence.
${\sum (-}_{k = 1}^{24} k)$