Book edition 6th

Author(s) Sullivan

Pages 1200 pages

ISBN 9780321795465

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Short Answer

In Problems 71-82, find the sum of each sequence.
$\sum_{k = 10}^{60} (2 k)$

The sum of this sequence is 3570.

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1. Write the given information.

The sum of sequence:

$\sum_{k = 10}^{60} (2 k)$

Step 2. Use the property of sequences.

Using the property of sequences:

${\sum (c a_{k})}_{k = 1}^{n} = c {\sum a_{k}}_{k = 1}^{n} S o, {\sum (2 k)}_{k = 1}^{n} = 2 {\sum k}_{k = 1}^{n}$

Step 3. Use the formula for sum of sequences of n real numbers.

The formula for summation:

${\sum k}_{k = 10}^{60} = {\sum k}_{k = 1}^{60} {- \sum k}_{k = 1}^{9} \Rightarrow {\sum k}_{k = 10}^{60} = \frac{60 (60 + 1)}{2} - \frac{9 (9 + 1)}{2} \Rightarrow {\sum k}_{k = 10}^{60} = 30 \times 61 - 9 \times 5 \Rightarrow {\sum k}_{k = 10}^{60} = 1830 - 45 \Rightarrow {\sum k}_{k = 10}^{60} = 1785$

Step 4. Use the property of sequences from Step 2.

Using the property of sequences gives:

${\sum k}_{k = 10}^{60} = 1785 \Rightarrow {2 \sum k}_{k = 10}^{60} = 2 \times 1785 \Rightarrow {2 \sum k}_{k = 10}^{60} = 3570$

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Precalculus Enhanced with Graphing Utilities

Answers without the blur.

Short Answer

In Problems 71-82, find the sum of each sequence.
$\sum_{k = 10}^{60} (2 k)$

Step by Step Solution

Step 1. Write the given information.

Step 2. Use the property of sequences.

Step 3. Use the formula for sum of sequences of n real numbers.

Step 4. Use the property of sequences from Step 2.

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Precalculus Enhanced with Graphing Utilities

Answers without the blur.

Short Answer

In Problems 71-82, find the sum of each sequence.∑k=1060(2k)

Step by Step Solution

Step 1. Write the given information.

Step 2. Use the property of sequences.

Step 3. Use the formula for sum of sequences of n real numbers.

Step 4. Use the property of sequences from Step 2.

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In Problems 71-82, find the sum of each sequence.
$\sum_{k = 10}^{60} (2 k)$