Book edition 6th

Author(s) Sullivan

Pages 1200 pages

ISBN 9780321795465

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Short Answer

In Problems 71-82, find the sum of each sequence.
$\sum_{k = 8}^{40} (- 3 k)$

The sum of this sequence is -2376.

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1. Write the given information.

The sum of sequence:

$\sum_{k = 8}^{40} (- 3 k)$

Step 2. Use the property of sequences.

Using the property of sequences: ${\sum (c a_{k})}_{k = 1}^{n} = c {\sum a_{k}}_{k = 1}^{n} S o, {\sum (- 3 k)}_{k = 1}^{n} = - 3 {\sum k}_{k = 1}^{n}$

Step 3. Use the formula for sum of sequences of n real numbers

${\sum k}_{k = 8}^{40} = {\sum k}_{k = 1}^{40} {- \sum k}_{k = 1}^{7} \Rightarrow {\sum k}_{k = 8}^{40} = \frac{40 (40 + 1)}{2} - \frac{7 (7 + 1)}{2} \Rightarrow {\sum k}_{k = 8}^{40} = 20 \times 41 - 7 \times 4 \Rightarrow {\sum k}_{k = 8}^{40} = 820 - 28 \Rightarrow {\sum k}_{k = 8}^{40} = 792$

Step 4. Use the property of sequences from Step 2.

Using the property of sequences gives:

${\sum k}_{k = 8}^{40} = 792 \Rightarrow (- {3) \sum k}_{k = 8}^{40} = - 3 \times 792 \Rightarrow {(- 3) \sum k}_{k = 8}^{40} = - 2376$

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Precalculus Enhanced with Graphing Utilities

Answers without the blur.

Short Answer

In Problems 71-82, find the sum of each sequence.
$\sum_{k = 8}^{40} (- 3 k)$

Step by Step Solution

Step 1. Write the given information.

Step 2. Use the property of sequences.

Step 3. Use the formula for sum of sequences of n real numbers

Step 4. Use the property of sequences from Step 2.

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Precalculus Enhanced with Graphing Utilities

Answers without the blur.

Short Answer

In Problems 71-82, find the sum of each sequence.∑k=840(-3k)

Step by Step Solution

Step 1. Write the given information.

Step 2. Use the property of sequences.

Step 3. Use the formula for sum of sequences of n real numbers

Step 4. Use the property of sequences from Step 2.

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In Problems 71-82, find the sum of each sequence.
$\sum_{k = 8}^{40} (- 3 k)$