Book edition 6th

Author(s) Sullivan

Pages 1200 pages

ISBN 9780321795465

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Short Answer

Solve each system of equations. If the system has no solution, say that it is inconsistent.
$\{\begin{matrix} 5 x - y = 21 \\ 2 x + 3 y = - 12 \end{matrix}$

The solution of the given system of equation is $x = 3, y = - 6; (3, - 6)$ .

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1. Given information.

The given equations are:

$\begin{array}{rcl} 5 x - y & = & 21 \\ 2 x + 3 y & = & - 12 \end{array}$

Step 2. Determine the value of one variable by substitution.

The first equation can be written as:

$\begin{array}{rcl} - y & = & 21 - 5 x \\ y & = & 5 x - 21 \end{array}$

Substitute this in the second equation.

$\begin{array}{rcl} 2 x + 3 (5 x - 21) & = & - 12 \\ 2 x + 15 x - 63 & = & - 12 \\ 17 x & = & - 12 + 63 \\ x & = & \frac{51}{17} \\ x & = & 3 \end{array}$

Step 3. Determine the value of another variable.

Substitute $x = 3$ in $y = 5 x - 21$ .

$\begin{array}{rcl} y & = & 5 (3) - 21 \\ = & 15 - 21 \\ = & - 6 \end{array}$

The solution of the given system of equation is role="math" $x = 3, y = - 6; (3, - 6)$ .

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Precalculus Enhanced with Graphing Utilities

Answers without the blur.

Short Answer

Solve each system of equations. If the system has no solution, say that it is inconsistent.
$\{\begin{matrix} 5 x - y = 21 \\ 2 x + 3 y = - 12 \end{matrix}$

Step by Step Solution

Step 1. Given information.

Step 2. Determine the value of one variable by substitution.

Step 3. Determine the value of another variable.

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Precalculus Enhanced with Graphing Utilities

Answers without the blur.

Short Answer

Solve each system of equations. If the system has no solution, say that it is inconsistent.5x-y=212x+3y=-12

Step by Step Solution

Step 1. Given information.

Step 2. Determine the value of one variable by substitution.

Step 3. Determine the value of another variable.

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Solve each system of equations. If the system has no solution, say that it is inconsistent.
$\{\begin{matrix} 5 x - y = 21 \\ 2 x + 3 y = - 12 \end{matrix}$