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Q. 7

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Precalculus Enhanced with Graphing Utilities
Found in: Page 772
Precalculus Enhanced with Graphing Utilities

Precalculus Enhanced with Graphing Utilities

Book edition 6th
Author(s) Sullivan
Pages 1200 pages
ISBN 9780321795465

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Short Answer

Graph each equation of the system. Then solve the system to find the points of intersection.

y=36-x2y=8-x

Solutions of system of equationsy=36-x2y=8-x are (4+2,4-2) & (4-2,4+2) and the graph is

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Step by Step Solution

Step 1. Given data  

The given system of equations is

y=36-x2 (i)y=8-x (ii)

Step 2. Graph of the system of equations  

Plot the graph of y=36-x2 & y=8-xon same cartesian plane

Step 3. Solution of system  

Equate both equations

36-x2=8-x36-x2=8-x236-x2=x2-16x+642x2-16x+28=0

use quadratic formula

x=-b±b2-4ac2ax=-(-16)±(-16)2-4(2)(28)2(2)x=16±324x=4±2

Step 4. Solution of system  

Substitute x=4+2 in equation ii

y=8-xy=8-4+2y=4-2

Substitutex=4-2 in equation ii

y=8-xy=8-4-2y=4+2

So solutions of the system are (4+2,4-2) & (4-2,4+2)

Step 6. Point of intersection 

Locate (4+2,4-2) & (4-2,4+2) for point of interception in the graph of a system of equations

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