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Q. 86

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Precalculus Enhanced with Graphing Utilities
Found in: Page 411
Precalculus Enhanced with Graphing Utilities

Precalculus Enhanced with Graphing Utilities

Book edition 6th
Author(s) Sullivan
Pages 1200 pages
ISBN 9780321795465

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Short Answer

In Problem 85 and 86 graph each of the function

g(x)=2sinx if 0xπcosx+1 ifπ<x2π

Graph of the given function

See the step by step solution

Step by Step Solution

Step 1.Given information

The given function g(x)=2sinx if 0xπcosx+1 ifπ<x2π

Now graph each function as follows.
The given function is a composite function of function y=2sinx for the interval 0xπ

and function y=cosx+1 for the interval π<x2π.

Here domain of the function g(x) is [0,2π] and its range is 1 to - 1.

Step 2.Calculate some points for sinx in their given domain  

Choose different x-values and calculate the corresponding y=sinx values.

x y=2sinx (x,y)
0 2sin0=0 (0,0)
π4 2sinπ4=222 =2(π4,2)
π2 2sinπ2=2(1) =2 (π2,2)
3π4 2sin3π4=222 =2 3π4,2
π 2sinπ=0 π,0

Step 3.Calculate some points for cosx in their given domain 

Choose different -xvalues and calculate the y=cosx+1 corresponding values.
x y=cosx+1 (x,y)
5π4 cos5π4+1=-22+1 =0.293 5π4,0.293
role="math" localid="1646328747587" 3π2 cos3π2+1=0+1 =1 3π2,1
7π4 cos7π4=22+1 =1.7071 7π4,1.7071
2π cos(2π)+1=1+1 =2 2π,2

Step 4.Plot the above ordered pairs on the graph and connect them with a smooth curve. 

Thus function g(x) is graphed as a composite function of y=2sinx in blue and y=cosx+1 in pink shown below:

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