Short Answer

Use a graphing device to graph the ellipse.
$\frac{x^{2}}{25} + \frac{y^{2}}{20} = 1$

Hence, the graph of the ellipse $<\frac{x^{2}}{25} + \frac{y^{2}}{20} = 1>$ is as shown:

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1. Given information.

Given the equation of ellipse $<\frac{x^{2}}{25} + \frac{y^{2}}{20} = 1>$ .

substitution method.

Step 2. Write down the concept.

Comparing the given equation with the standard equation,

$\begin{array}{l} \Rightarrow a^{2} = 25 \\ \Rightarrow a = 5 \\ \Rightarrow b^{2} = 20 \\ \Rightarrow b = 4.47 \\ \Rightarrow c = \sqrt{25 - 20} \\ \Rightarrow c = \sqrt{5} \\ \Rightarrow c = 2.24 \end{array}$

Hence,

The coordinates of the vertices are $(\pm 5, 0)$

The coordinates of the foci are $(\pm 2.24, 0)$

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Precalculus Mathematics for Calculus

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Short Answer

Use a graphing device to graph the ellipse.
$\frac{x^{2}}{25} + \frac{y^{2}}{20} = 1$

Step by Step Solution

Step 1. Given information.

Step 2. Write down the concept.

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Precalculus Mathematics for Calculus

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Short Answer

Use a graphing device to graph the ellipse.x225+y220=1

Step by Step Solution

Step 1. Given information.

Step 2. Write down the concept.

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Use a graphing device to graph the ellipse.
$\frac{x^{2}}{25} + \frac{y^{2}}{20} = 1$