A biologist has two brine solutions, one
containing 5% salt and another containing 20% salt. How
many milliliters of each solution should she mix to obtain
1 L of a solution that contains 14% salt?
For the given mixture problem, we get that 400 ml of 5% salt solution should be mixed with 600 ml of 20% salt solution.
x = number of ml of the 5% salt brine solution.
y = number of ml of the 20% salt brine solution.
Since 1L = 1000ml
Thus, the total amount of brine solution would be
x + y = 1000 …….(1)
Also from the given information we have
0.05x + 0.2y = 140 ……….(2)
Solving equation (1) and (2) we have,
From (1) we get
y = 1000 - x
Substituting this in equation (2), we get
0.05x + 0.2(1000-x) = 140
0.05x + 200 -0.02x = 140
-0.15x = -60
x = 400
y = 1000-400
y = 600
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