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6.25
Expert-verifiedThe analysis of this section applies also to linear polyatomic molecule for which no rotation about the axis of symmetry is possible .An example is CO2, with e=0.000049 eV. Estimate the rotational partition function for a CO2 molecule at room temperature.(Note that the arrangement of the atom is OCO, and the two oxygen atoms are identical.)
Zrot =kT/2
=263.78
=264
Here, k is Boltzmann's constant, T is the room temperature, and is a constant which sets energy scale for rotational excitations.
Zmol =kT/2∈
=(8.617*10-3-eV)(300K)/2(0.000049eV)
=263.78
=264
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