Book edition 1st

Author(s) Daniel V. Schroeder

Pages 356 pages

ISBN 9780201380279

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Short Answer

Suppose you have a gas containing hydrogen molecules and oxygen molecules, in thermal equilibrium. Which molecule are moving faster, on average? By what factor?

In thermal equilibrium, hydrogen molecules moves faster by a factor of 4

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1 : Concept of thermal equilibrium which relates with the rms speed of molecules.

Thermal equilibrium refers that both the molecules have same temperature, Hence we can write

$\frac{3}{2} K T = \frac{1}{2} m v^{2} v = \sqrt{\frac{3 K T}{m}}$

Step 2 : Relation of speed with molar mass.

From the above equation we can say that $v α \frac{1}{\sqrt{m}}$

Thus the molecule with least mass will have maximum rms speed.

Now O₂ had molecular mass of 32 & H₂ has molecular mass of 2

$\frac{{m_{H}}_{2}}{{m_{O}}_{2}} = 16$

Step 3 : Arriving at the result.

Thus we can say that hydrogen with least mass has the maximum rms speed and

$\frac{v_{H_{2}}}{v_{O_{2}}} = \sqrt{\frac{m_{O_{2}}}{m_{H_{2}}} =} \sqrt{\frac{1}{16}} v_{O_{2}} = 4 v_{H_{2}}$

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An Introduction to Thermal Physics

Answers without the blur.

Short Answer

Suppose you have a gas containing hydrogen molecules and oxygen molecules, in thermal equilibrium. Which molecule are moving faster, on average? By what factor?

Step by Step Solution

Step 1 : Concept of thermal equilibrium which relates with the rms speed of molecules.

Step 2 : Relation of speed with molar mass.

Step 3 : Arriving at the result.

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An Introduction to Thermal Physics

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Short Answer

Suppose you have a gas containing hydrogen molecules and oxygen molecules, in thermal equilibrium. Which molecule are moving faster, on average? By what factor?

Step by Step Solution

Step 1 : Concept of thermal equilibrium which relates with the rms speed of molecules.

Step 2 : Relation of speed with molar mass.

Step 3 : Arriving at the result.

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