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Q.1.1.

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An Introduction to Thermal Physics
Found in: Page 5
An Introduction to Thermal Physics

An Introduction to Thermal Physics

Book edition 1st
Author(s) Daniel V. Schroeder
Pages 356 pages
ISBN 9780201380279

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Short Answer

The Fahrenheit temperature scale is defined so that ice melts at 320 F and water boils at 2120 F.

(a) Derive the formula for converting from Fahrenheit to Celsius and back

(b) What is absolute zero on the Fahrenheit scale?

(a)95°C+32=°F

(b) -459.67°F

See the step by step solution

Step by Step Solution

Part (a) Step 1 : Fahrenheit scales values of freezing point and boiling point.

Fahrenheit freezing point of water = 32°F

Fahrenheit boiling point of water = 212°F

212 - 32 = 180°F between the freezing point and boiling point of water.

Part (a) Step 2 :  Celsius scales values of freezing and boiling point.

Celsius freezing point of water = 0°C

Celsius boiling point of water = 100°C

100 - 0 = 100°C between the freezing point and boiling point of water.

Part (a) Step 3 : Ratio for Celsius to Fahrenheit scale values. 

The ratio for Celsius to Fahrenheit of 100180 = 59and the ratio of Fahrenheit to Celsius of 180100 = 95

then 32°F = 0°C

Hence the formula for degree Celsius to Fahrenheit is localid="1649151785065" 95°C + 32 =°F

Part (b) Step 1: Absolute zero in celsius

Absolute zero = 0K

K - 273.15 = °C

°C = 0 - 273.15 = -273.15°C

Part (b) Step 2: Absolute zero in Fahrenheit

we know that °F =95°C + 32

°F = 95(-273.15) + 32

°F = -459.67°F

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