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Expert-verified Found in: Page 5 ### An Introduction to Thermal Physics

Book edition 1st
Author(s) Daniel V. Schroeder
Pages 356 pages
ISBN 9780201380279 # The Fahrenheit temperature scale is defined so that ice melts at 320 F and water boils at 2120 F.(a) Derive the formula for converting from Fahrenheit to Celsius and back (b) What is absolute zero on the Fahrenheit scale?

(a)$\frac{9}{5}°C+32=°F$

(b) -459.67$°F$

See the step by step solution

## Part (a) Step 1 : Fahrenheit scales values of freezing point and boiling point.

Fahrenheit freezing point of water = 32$°F$

Fahrenheit boiling point of water = 212$°F$

212 - 32 = 180$°F$ between the freezing point and boiling point of water.

## Part (a) Step 2 :  Celsius scales values of freezing and boiling point.

Celsius freezing point of water = 0$°C$

Celsius boiling point of water = 100$°C$

100 - 0 = 100$°C$ between the freezing point and boiling point of water.

## Part (a) Step 3 : Ratio for Celsius to Fahrenheit scale values.

The ratio for Celsius to Fahrenheit of $\frac{100}{180}=\frac{5}{9}$and the ratio of Fahrenheit to Celsius of $\frac{180}{100}=\frac{9}{5}$

then 32$°F$ = 0$°C$

Hence the formula for degree Celsius to Fahrenheit is localid="1649151785065" ${}^{}\frac{9}{5}°C+32=°F$

## Part (b) Step 1: Absolute zero in celsius

Absolute zero = 0K

K - 273.15 = $°C$

$°C$ = 0 - 273.15 = -273.15$°C$

## Part (b) Step 2: Absolute zero in Fahrenheit

we know that $°F=\frac{9}{5}°C+32$

$°F=\frac{9}{5}\left(-273.15\right)+32$

$°F=-459.67°F$ ### Want to see more solutions like these? 