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Q.1.1.

Expert-verifiedFound in: Page 5

Book edition
1st

Author(s)
Daniel V. Schroeder

Pages
356 pages

ISBN
9780201380279

The Fahrenheit temperature scale is defined so that ice melts at 32^{0} F and water boils at 212^{0} F.

(a) Derive the formula for converting from Fahrenheit to Celsius and back

(b) What is absolute zero on the Fahrenheit scale?

(a)$\frac{9}{5}\xb0C+32=\xb0F$

(b) -459.67$\xb0F$

Fahrenheit freezing point of water = 32$\xb0F$

Fahrenheit boiling point of water = 212$\xb0F$

212 - 32 = 180$\xb0F$ between the freezing point and boiling point of water.

Celsius freezing point of water = 0$\xb0C$

Celsius boiling point of water = 100$\xb0C$

100 - 0 = 100$\xb0C$ between the freezing point and boiling point of water.

The ratio for Celsius to Fahrenheit of $\frac{100}{180}=\frac{5}{9}$and the ratio of Fahrenheit to Celsius of $\frac{180}{100}=\frac{9}{5}$

then 32$\xb0F$ = 0$\xb0C$

Hence the formula for degree Celsius to Fahrenheit is localid="1649151785065" ${}^{}\frac{9}{5}\xb0C+32=\xb0F$

Absolute zero = 0K

K - 273.15 = $\xb0C$

$\xb0C$ = 0 - 273.15 = -273.15$\xb0C$

we know that $\xb0F=\frac{9}{5}\xb0C+32$

$\xb0F=\frac{9}{5}(-273.15)+32$

$\xb0F=-459.67\xb0F$

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