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Found in: Page 129

Book edition 1st

Author(s) Daniel V. Schroeder

Pages 356 pages

ISBN 9780201380279

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Short Answer

Suppose that heat leaks into your kitchen refrigerator at an average rate of 300 watts. Assuming ideal operation, how much power must it draw from the wall?

The power drawn from wall is 57.69 W.

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1 : Given information

Assume temperatures T1 = 250 K and T2 = 298 KPower leak = 300 W

Step 2 : Explanation

COP can be found by using $COP = \frac{T_{1}}{T_{2} - T_{1}}$

Substitute the values

$COP = \frac{250}{298 - 250} C O P = 5.2$

The amount of power drawn from the wall is:

$P = \frac{P_{avg}}{C O P} P = \frac{300 W}{5.2} P = 57.69 W$

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Short Answer

Suppose that heat leaks into your kitchen refrigerator at an average rate of 300 watts. Assuming ideal operation, how much power must it draw from the wall?

Step by Step Solution

Step 1 : Given information

Step 2 : Explanation

Most popular questions for Physics Textbooks

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Answers without the blur.

Short Answer

Suppose that heat leaks into your kitchen refrigerator at an average rate of 300 watts. Assuming ideal operation, how much power must it draw from the wall?

Step by Step Solution

Step 1 : Given information

Step 2 : Explanation

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