• :00Days
  • :00Hours
  • :00Mins
  • 00Seconds
A new era for learning is coming soonSign up for free
Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration

5.18

Expert-verified
An Introduction to Thermal Physics
Found in: Page 163
An Introduction to Thermal Physics

An Introduction to Thermal Physics

Book edition 1st
Author(s) Daniel V. Schroeder
Pages 356 pages
ISBN 9780201380279

Answers without the blur.

Just sign up for free and you're in.

Illustration

Short Answer

Imagine that you drop a brick on the ground and it lands with a thud. Apparently the energy of this system tends to spontaneously decrease. Explain why.

The energy is transferred from the brick to the ground, so the energy of the system tends to spontaneously decrease.

See the step by step solution

Step by Step Solution

Given

A brick is dropped to the ground and it lands with a thud.

Energy of this system tends to spontaneously decrease, explain why?

Explanation

Helmholtz free energy can be determined by
F=U-T SWhere, F= Helmholtz free energy, U=Internal energy,T=absolute temperature of the system and S=entropy of the system.The total energy of the brick = kinetic energy + potential energy

From the law of energy conservation this is always constant.

When the brick hits the ground, its kinetic energy is zero, but the potential energy remains the same. The kinetic energy is redistributed into the thermal energy of the molecules of the brick and to the ground where the brick hits.

So a part of the energy is transferred from the brick to the ground.

Therefore the energy of the system tends to spontaneously decrease.

Most popular questions for Physics Textbooks

In this problem you will derive approximate formulas for the shapes of the phase boundary curves in diagrams such as Figures 5.31 and 5.32, assuming that both phases behave as ideal mixtures. For definiteness, suppose that the phases are liquid and gas.

(a) Show that in an ideal mixture of A and B, the chemical potential of species A can be written μA=μA°+kTln(1-x)where A is the chemical potential of pure A (at the same temperature and pressure) and x=NB/NA+NB. Derive a similar formula for the chemical potential of species B. Note that both formulas can be written for either the liquid phase or the gas phase.

(b) At any given temperature T, let x1 and xg be the compositions of the liquid and gas phases that are in equilibrium with each other. By setting the appropriate chemical potentials equal to each other, show that x1 and xg obey the equations =1-xl1-xg=eΔGA°/RT and xlxg=eΔGB°/RT and where ΔG° represents the change in G for the pure substance undergoing the phase change at temperature T.

(c) Over a limited range of temperatures, we can often assume that the main temperature dependence of ΔG°=ΔH°-TΔS° comes from the explicit T; both ΔH° and ΔS° are approximately constant. With this simplification, rewrite the results of part (b) entirely in terms of ΔHA°,ΔHB° TA, and TB (eliminating ΔG and ΔS). Solve for x1 and xg as functions of T.

(d) Plot your results for the nitrogen-oxygen system. The latent heats of the pure substances areΔHN2°=5570 J/mol and ΔHO2°=6820 J/mol. Compare to the experimental diagram, Figure 5.31.

(e) Show that you can account for the shape of Figure 5.32 with suitably chosen ΔH° values. What are those values?

Icon

Want to see more solutions like these?

Sign up for free to discover our expert answers
Get Started - It’s free

Recommended explanations on Physics Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.