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Expert-verified Found in: Page 775 ### College Physics (Urone)

Book edition 1st Edition
Author(s) Paul Peter Urone
Pages 1272 pages
ISBN 9781938168000 # Standard automobile batteries have six lead-acid cells in series, creating a total emf of 12.0 V. What is the emf of an individual lead-acid cell?

The emf of an individual lead-acid cell is 2 V.

See the step by step solution

## Step 1: Principle and formula

Assume emf of individual lead acid cell is . Since, there is series combination of cell which makes battery. Thus, the net emf of a battery is given as,

E = e + e + e + e + e+ e

= 6E

## Step 2: Calculation of each cell

When cells are connected in series, the resultant EMF is the algebraic sum of EMF of individual cells. Therefore, here the EMF of individual Lead acid cell is

$\mathrm{E}=\frac{12\mathrm{V}}{6}\phantom{\rule{0ex}{0ex}}=2\mathrm{V}$

However actual EMF is 2 V, slightly greater than the value obtained. ### Want to see more solutions like these? 