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Q15CQ

Expert-verifiedFound in: Page 772

Book edition
1st Edition

Author(s)
Paul Peter Urone

Pages
1272 pages

ISBN
9781938168000

**Given a battery, an assortment of resistors, and a variety of voltage and current measuring devices, describe how you would determine the internal resistance of the battery.**

Internal resistance is** **${\mathrm{R}}_{\mathrm{int}}={\mathrm{R}}_{\mathrm{tot}}-{\mathrm{R}}_{\mathrm{ext}.}$

**Internal resistance is referred to as the opposed flow of current by the cells itself resulting in the generation of heat.**

To determine the internal resistance of the battery, we need to have some information. The first would be raw voltage(${\mathrm{U}}_{\mathrm{raw}}$ ) with no current flowing through. Next, we need to attach to the circuit, between the poles, a resistor with known resistance ${\mathrm{R}}_{\mathrm{ext}}$ . Then we can calculate the expected current, which would happen if the source was perfect, with no internal resistance. After that, we can measure real current, ${\mathrm{I}}_{\mathrm{real}}$ , and calculate total resistance as:

${\mathrm{R}}_{\mathrm{tot}}=\frac{{\mathrm{U}}_{\mathrm{raw}}}{{\mathrm{I}}_{\mathrm{real}}}$

Finally, internal resistance is calculated as:

**${\mathrm{R}}_{\mathrm{int}}={\mathrm{R}}_{\mathrm{tot}}-{\mathrm{R}}_{\mathrm{ext}}$**

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