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College Physics (Urone)
Found in: Page 772
College Physics (Urone)

College Physics (Urone)

Book edition 1st Edition
Author(s) Paul Peter Urone
Pages 1272 pages
ISBN 9781938168000

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Short Answer

Apply the loop rule to loop \({\rm{afedcba}}\) in Figure \({\rm{21}}{\rm{.47}}\)

Applying loop rule in \({\rm{afedcba}}\) gives us: \({I_1}\left( {{r_1} + {R_1} + {R_4}} \right) + {I_2}({R_3} + {r_3} + {r_4}) - {E_1} - {E_3} + {E_4} = 0\)

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Step by Step Solution

TABLE OF CONTENTS :
TABLE OF CONTENTS

Step 1: The Loop Rule

According to this rule, the sum of potential differences of all the components in a loop should be zero,

Step 2: Evaluating the loop

Applying the loop rule in loop afedcba, we get

\(\begin{array}{l}{I_1}{r_1} - {E_1} + {I_1}{R_4} + {E_4} + {I_2}{r_4} + {I_2}{r_3} - {E_3} + {I_2}{R_3} + {I_1}{R_1} = 0\\{I_1}\left( {{r_1} + {R_1} + {R_4}} \right) + {I_2}({R_3} + {r_3} + {r_4}) - {E_1} - {E_3} + {E_4} = 0\end{array}\)

Therefore, we got the relation: \({I_1}\left( {{r_1} + {R_1} + {R_4}} \right) + {I_2}({R_3} + {r_3} + {r_4}) - {E_1} - {E_3} + {E_4} = 0\)

Most popular questions for Physics Textbooks

The \({\rm{RC}}\) time constant in heart defibrillation is crucial to limiting the time the current flows. If the capacitance in the defibrillation unit is fixed, how would you manipulate resistance in the circuit to adjust the \({\rm{RC}}\) constant \(\tau \)? Would an adjustment of the applied voltage also beaded to ensure that the current delivered has an appropriate value?

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